Inverse function theorem - the easy half #
In this file we prove that g' (f x) = (f' x)โปยน provided that f is strictly differentiable at
x, f' x โ 0, and g is a local left inverse of f that is continuous at f x. This is the
easy half of the inverse function theorem: the harder half states that g exists.
For a more detailed overview of one-dimensional derivatives in mathlib, see the module docstring of
Analysis/Calculus/Deriv/Basic.
Keywords #
derivative, inverse function
If f (g y) = y for y in some neighborhood of a, g is continuous at a, and f has an
invertible derivative f' at g a in the strict sense, then g has the derivative f'โปยน at a
in the strict sense.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f is an open partial homeomorphism defined on a neighbourhood of f.symm a, and f has a
nonzero derivative f' at f.symm a in the strict sense, then f.symm has the derivative f'โปยน
at a in the strict sense.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f (g y) = y for y in some neighborhood of a, g is continuous at a, and f has an
invertible derivative f' at g a, then g has the derivative f'โปยน at a.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
If f is an open partial homeomorphism defined on a neighbourhood of f.symm a, and f has a
nonzero derivative f' at f.symm a, then f.symm has the derivative f'โปยน at a.
This is one of the easy parts of the inverse function theorem: it assumes that we already have an inverse function.
Alias of HasDerivAt.tendsto_nhdsNE.
If a function is equal to a constant at a set of points that accumulates to x in s,
then its derivative within s at x equals zero,
either because it has derivative zero or because it isn't differentiable at this point.
If a function is equal to a constant at a set of points that accumulates to x,
then its derivative at x equals zero,
either because it has derivative zero or because it isn't differentiable at this point.