Measure with a given density with respect to another measure #
For a measure μ on α and a function f : α → ℝ≥0∞, we define a new measure μ.withDensity f.
On a measurable set s, that measure has value ∫⁻ a in s, f a ∂μ.
An important result about withDensity is the Radon-Nikodym theorem. It states that, given measures
μ, ν, if HaveLebesgueDecomposition μ ν then μ is absolutely continuous with respect to
ν if and only if there exists a measurable function f : α → ℝ≥0∞ such that
μ = ν.withDensity f.
See MeasureTheory.Measure.absolutelyContinuous_iff_withDensity_rnDeriv_eq.
Given a measure μ : Measure α and a function f : α → ℝ≥0∞, μ.withDensity f is the
measure such that for a measurable set s we have μ.withDensity f s = ∫⁻ a in s, f a ∂μ.
Equations
- μ.withDensity f = MeasureTheory.Measure.ofMeasurable (fun (s : Set α) (x : MeasurableSet s) => ∫⁻ (a : α) in s, f a ∂μ) ⋯ ⋯
Instances For
In the next theorem, the s-finiteness assumption is necessary. Here is a counterexample
without this assumption. Let α be an uncountable space, let x₀ be some fixed point, and consider
the σ-algebra made of those sets which are countable and do not contain x₀, and of their
complements. This is the σ-algebra generated by the sets {x} for x ≠ x₀. Define a measure equal
to +∞ on nonempty sets. Let s = {x₀} and f the indicator of sᶜ. Then
∫⁻ a in s, f a ∂μ = 0. Indeed, consider a simple functiong ≤ f. It vanishes ons. Then∫⁻ a in s, g a ∂μ = 0. Taking the supremum overggives the claim.μ.withDensity f s = +∞. Indeed, this is the infimum ofμ.withDensity f tover measurable setstcontainings. Assis not measurable, such a settcontains a pointx ≠ x₀. Thenμ.withDensity f t ≥ μ.withDensity f {x} = ∫⁻ a in {x}, f a ∂μ = μ {x} = +∞. One checks thatμ.withDensity f = μ, whileμ.restrict sgives zero mass to sets not containingx₀, and infinite mass to those that contain it.
Alias of the forward direction of MeasureTheory.withDensity_eq_zero_iff.
This is Exercise 1.2.1 from [tao2010]. It allows you to express integration of a measurable
function with respect to (μ.withDensity f) as an integral with respect to μ, called the base
measure. μ is often the Lebesgue measure, and in this circumstance f is the probability density
function, and (μ.withDensity f) represents any continuous random variable as a
probability measure, such as the uniform distribution between 0 and 1, the Gaussian distribution,
the exponential distribution, the Beta distribution, or the Cauchy distribution (see Section 2.4
of [wasserman2004]). Thus, this method shows how to one can calculate expectations, variances,
and other moments as a function of the probability density function.
The Lebesgue integral of g with respect to the measure μ.withDensity f coincides with
the integral of f * g. This version assumes that g is almost everywhere measurable. For a
version without conditions on g but requiring that f is almost everywhere finite, see
lintegral_withDensity_eq_lintegral_mul_non_measurable
If f is almost everywhere positive, then μ ≪ μ.withDensity f. See also
withDensity_absolutelyContinuous for the reverse direction, which always holds.
If μ is a σ-finite measure, then so is μ.withDensity fun x ↦ f x
for any ℝ≥0-valued function f.
If μ is an s-finite measure, then so is μ.withDensity f.
If μ ≪ ν and ν is s-finite, then μ is s-finite.
In a countable space, every measure is s-finite.