The characteristic predicate of tensor product #
Main definitions #
IsTensorProduct: A predicate onf : M₁ →ₗ[R] M₂ →ₗ[R] Mexpressing thatfrealizesMas the tensor product ofM₁ ⊗[R] M₂. This is defined by requiring the liftM₁ ⊗[R] M₂ → Mto be bijective.IsBaseChange: A predicate on anR-algebraSand a mapf : M →ₗ[R] NwithNbeing anS-module, expressing thatfrealizesNas the base change ofMalongR → S.Algebra.IsPushout: A predicate on the following diagram of scalar towers
asserting that is a pushout diagram (i.e.R → S ↓ ↓ R' → S'S' = S ⊗[R] R')
Main results #
TensorProduct.isBaseChange:S ⊗[R] Mis the base change ofMalongR → S.
Given a bilinear map f : M₁ →ₗ[R] M₂ →ₗ[R] M, IsTensorProduct f means that
M is the tensor product of M₁ and M₂ via f.
This is defined by requiring the lift M₁ ⊗[R] M₂ → M to be bijective.
Equations
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If M is the tensor product of M₁ and M₂, it is linearly equivalent to M₁ ⊗[R] M₂.
Equations
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If M is the tensor product of M₁ and M₂, we may lift a bilinear map M₁ →ₗ[R] M₂ →ₗ[R] M'
to a M →ₗ[R] M'.
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The tensor product of a pair of linear maps between modules.
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Given an R-algebra S and an R-module M, an S-module N together with a map
f : M →ₗ[R] N is the base change of M to S if the map S × M → N, (s, m) ↦ s • f m is the
tensor product.
Equations
- IsBaseChange S f = IsTensorProduct (↑R ((Algebra.linearMap S (Module.End S (M →ₗ[R] N))).flip f))
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Suppose f : M →ₗ[R] N is the base change of M along R → S. Then any R-linear map from
M to an S-module factors through f.
Equations
- h.lift g = { toAddHom := (IsTensorProduct.lift h (↑R ((Algebra.linearMap S (Module.End S (M →ₗ[R] Q))).flip g))).toAddHom, map_smul' := ⋯ }
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The base change of M along R → S is linearly equivalent to S ⊗[R] M.
Equations
- h.equiv = { toAddHom := (↑(IsTensorProduct.equiv h)).toAddHom, map_smul' := ⋯, invFun := (IsTensorProduct.equiv h).invFun, left_inv := ⋯, right_inv := ⋯ }
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If N is the base change of M to A, then N ⊗[R] P is the base change
of M ⊗[R] P to A. This is simply the isomorphism
A ⊗[S] (M ⊗[R] P) ≃ₗ[A] (A ⊗[S] M) ⊗[R] P.
If N is the base change of M to S and O the base change of M to T, then
O is the base change of N to T.
If N is the base change M to S, then O is the base change of M to T if and
only if O is the base change of N to T.
Let R be a commutative ring, S be an R-algebra, M be an R-module, P be an S
module, N be the base change of M to S, then P ⊗[S] N is isomorphic to P ⊗[R] M
as S-modules.
Equations
- hf.tensorEquiv P = (LinearEquiv.lTensor P hf.equiv.symm).trans (TensorProduct.AlgebraTensorModule.cancelBaseChange R S S P M)
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A type-class stating that the following diagram of scalar towers
R → S
↓ ↓
R' → S'
is a pushout diagram (i.e. S' = S ⊗[R] R')
- out : IsBaseChange S (IsScalarTower.toAlgHom R R' S').toLinearMap
Instances
The isomorphism S' ≃ S ⊗[R] R given Algebra.IsPushout R S R' S'.
Equations
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If S' = S ⊗[R] R', then any pair of R-algebra homomorphisms f : S → A and g : R' → A
such that f x and g y commutes for all x, y descends to a (unique) homomorphism S' → A.
Equations
- Algebra.pushoutDesc S' f g hf = (Algebra.TensorProduct.lift f g hf).comp (AlgHom.restrictScalars R ↑(Algebra.IsPushout.equiv R S R' S').symm)
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Let the following be a commutative diagram of rings
R → S → T
↓ ↓ ↓
R' → S' → T'
where the left-hand square is a pushout. Then the following are equivalent:
- the big rectangle is a pushout.
- the right-hand square is a pushout.
Note that this is essentially the isomorphism T ⊗[S] (S ⊗[R] R') ≃ₐ[T] T ⊗[R] R'.