Factorization of a map from measurability #
Consider f : X → Y
and g : X → Z
and assume that g
is measurable with respect to the pullback
along f
. Then g
factors though f
, which means that there exists h : Y → Z
such that
g = h ∘ f
.
TODO #
- Under certain assumptions, the factorization map
h
is measurable. This is the content of the Doob-Dynkin lemma.
If a function g
is measurable with respect to the pullback along some function f
,
then to prove g x = g y
it is enough to prove f x = f y
.
If a function g
is strongly measurable with respect to the pullback along some function f
,
then to prove g x = g y
it is enough to prove f x = f y
.
TODO: under certain assumptions, the factorization map h
is measurable. This is the content of the
Doob-Dynkin lemma.
If a function is measurable with respect to the σ-algebra generated by the first coordinates, then it only depends on those first coordinates.
If a function is strongly measurable with respect to the σ-algebra generated by the first coordinates, then it only depends on those first coordinates.
If a function is measurable with respect to the σ-algebra generated by the first coordinates, then it only depends on those first coordinates.
If a function is strongly measurable with respect to the σ-algebra generated by the first coordinates, then it only depends on those first coordinates.